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Is there any Standard that says that in every vessel, both a level gauge and another electronic level transmitter, say D/P type, should always be installed?

I was just wondering because in almost all of the vessels I saw, the two always go together.

Thanks.

Yes, it is required to install a level gauge with level transmitter. The level gauge is for local indication while the the level transmitter is for Remote indication. If there is a doubt in the remote indication you can always check the reading on the local level gauge.

I don't believe that there is a standard, but it is good engineering practice if the level in the vessel is a critical control parameter.

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No, there is no standard, it depends on the site.

If it's a critical application it might have more than one transmitter or the level transmitter might be backed up with High or Low level switch.

Level gauges are usually only used on clean liquids or where the tank is not agitated.

Roy

So it's just a good engineering practice but is not mentioned in any Standard. I thought there might have been a Standard for that.

Thanks!

Hello,

I need help. I am confused about how you determined the correlation between the P=F/A with the level of liquid in open tank since I know the increasing of liquid level on area will cause the pressure at datum line of the transmitter HP connection to increase also (Differential Pressure Transmitter). (Yes I know the result will be Kpa.) Why if I calculated it with another equation P=specific gravity*gravity*height of the tank, the result will be different? Can someone explain that?

I think you have the wrong formula, Area has nothing to do with the pressure
P = SG * Height

A simple way is to calculate the pressure of a column of water then multiply by SG.

Roy

Friend,

I don't understand well your question but here is the following:

Hydrostatic pressure (pressure created by a liquid or column liquid) is:

Pressure of liquid = Height * Sg (specific gravity)

You can do a relation from this P = F/A using the unit converter factors because 1 Psig = 27.7"H2O. Then if you have your level value in Psig or something like that, you must be making the following in order to get the real level.

For example if you have two psig in a gauge installed in the bottom of an open tank and the liquid inside the tank is only water, this two psig represents a level of about 56 "H2O because 2 x 27.7"H2O = 56"H2O, but if you have the same value (2 psig) with a liquid of SG = 0.65 then:

P = h * sg -------> h = P/sg -------> h = 56"H2O / 0.65 = 86" of that
liquid (0.65)

A liquid with specific gravity of 0.65 will need more height to create two psig of pressure.

If you have only water, it will need about 56" of height to create two psig of pressure.

I hope I helped you with this.

Regards,
Juan

Friend,

We have learned during our study that the Pressure, P (which is independent of cross section area of tank) at the bottom of the tank:

P = ROW * G * h

Where
ROW = Density of liquid
G = Gravitational constant
H = height of the liquid in tank

As per your formula, what is the effect of Gravitational Constant?

Thank you, roy, but what if the volume of the containers, e.g. an open or closed tank, are different although the heights are same? Isn't it if the volume of the containers are bigger the pressure also increases, or do I miss the perception?

No, if the column of fluid is 1/2" or several feet in diameter the pressure is the same. I think you are confusing the formula for force Pressure x Area. For a level transmitter you are only concerned with pressure. It helps think in terms of Head, e.g. Inches Water Column or Meters Water Column.

I think Juan Pinzon summed it up in his response.

Regards
Roy

hello,
you're right roy, I have just try using dp transmitter and the result when I measured the level are close to the equation of juan given thank you for your enlightment.