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Converting Hex to Floating point
Software, including programming, OS issues, etc. topic
Posted by Saeid Yousefpour on 5 September, 2009 - 11:05 am
Hi all.

I get a hex value from a device through serial port over modbus protocol. but I don't know how to convert it to equivalent fraction decimal.
for example:
I get : 41C41DC3
and it is : 24.51453

is any body familiar with algorithm?
also if there is a algorithm to convert binary to fraction decimal it would help.

or if there is any vb.net function to do that?

Thanks : Saeid_Yousefpour [at] yahoo.com


Posted by Bruce Durdle on 5 September, 2009 - 9:12 pm
It looks as if the value is encoded in IEEE 32-bit floating-point format.

The first bit is a sign bit - 1 = -, 0 = +

The next 8 bits are the exponent with a offset of 127 In your case
41C = s100 0001 1nnn and the exponent = 131 - 127 = 4.

The remainder is a normalised value between 1 and 2 - 01 and 10 in binary.

Since the first bit is always 1 it is always present and is not transmitted.

So the remaining bits are the binary fraction part - the first bit is worth 0.5, the 2nd bit 0.25, the 3rd 0.125 and so on.

Just looking at the first few bits, the value is (.)100 0100 0001 1100 = 0.5 + 0 x 0.25 + 0 x 0.125 + 0x 0.0625 + 1 x .03125 = 0.5 + .03125 = 0.53125

Add this to the 1 and the mantissa part is 1.53125. Multiply this by 2 to the power of the exponent = =2^4 = 16 and you get 1.53125 x 16 = 24.5 to 3 sig figs. Add in the rest of the bits and you'll get something approaching your value.

To recap,
The first bit is a sign bit s.

The next 8 bits represent 127+ n where n is the power of 2 to multiply by.

The mantissa is 1.bbb bbbb bbbb bbbb bbbb bbbb where each succeeding \b is weighted at 1/2 the value of the one before. The value represented is s 1. bbb bbbb bbbb bbbb bbbb bbbb x 2^n.

Hope this helps.
Cheers,
Bruce.


Posted by Saeid Yousefpour on 6 September, 2009 - 3:21 pm
Thank you Bruce. it works very good.


Posted by M Griffin on 5 September, 2009 - 10:56 pm
That is a single precision floating point number in "big-endian" (network order) byte order. I don't know if you can do this in VB DotNet, but in Python this is very easy.

Typing the following:
struct.unpack('!f', '\x41\xc4\x1d\xc3')

results in:
(24.514532089233398,)

As for binary to floating point, that is what the above is doing. The "hex" number is just a convenient way of representing a binary number in a printable format.


Posted by pvb on 6 September, 2009 - 2:00 am
I suppose the format is IEEE_754-1985

http://en.wikipedia.org/wiki/IEEE_754-1985#Single-precision_32-bit

It might be necessary to reverse the byte order depending on which type of CPU is used.


Posted by kevin grey on 6 September, 2009 - 10:42 am
Hi, There are a lot of examples and information about floating point number's.

I have created a simple vbscript that you should beable to use;

'number to be converted
'HexNumber = 1103371715 'as a decimal
HexNumber = &h41C41DC3 'as hex

'work out exponent get bits 23-30
exponent = HexNumber
For n = 0 To 22
exponent = exponent / 2
Next
exponent = exponent - 127
exponent = 2 ^ Int(exponent)
'Debug.Write Int(exponent) & vbcrlf

'work out Mantissa bits 0-22
'check each bit inturn and store result
decimalpart = 1
mantissa = 1
For n = 22 To 0 Step -1
decimalpart = decimalpart / 2
testbit = 2 ^ n
If (Hexnumber And testbit) Then
'Debug.Write testbit & " " & n & vbCrLf
mantissa = mantissa + decimalpart
End If
Next

Result = exponent * mantissa

MsgBox Result

Kevin


Posted by rana on 4 June, 2012 - 8:04 am
1-> reverse it like this C31DC4412
2-> convert it into binary its in ascii Hex
3-> then just assign the value to a float variable

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