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We need to install 125uF at 380Volts, three phase delta connected capacitor bank parallel to 37KW Motor.
1. The capacitor bank has to produce 125 uF at 380 Volts. the equivalent KVAr rating from the formula KVar = 2*pi*f*C*V2 is 5.6 KVar.
2. Due to the unavailability of the capacitor bank rated at 380 Volts, we proposed the Kvar rating of 7.5Kvar at 440 Volts.
3. On applying 380Volts to the capacitor rating of (7.5 Kvar, 440 Volts), the capacitor has to produce the Kvar rating of 5.6Kvar by the equation: Actual Kvar = Nameplate Kvar x (Applied Voltage)2/(Rated Voltage)2.
Will the microfarad rating also reduce accordingly?
What will be the capacitance output of the capacitor bank at this condition? Will the capacitance also reduce?
1. The capacitor bank has to produce 125 uF at 380 Volts. the equivalent KVAr rating from the formula KVar = 2*pi*f*C*V2 is 5.6 KVar.
2. Due to the unavailability of the capacitor bank rated at 380 Volts, we proposed the Kvar rating of 7.5Kvar at 440 Volts.
3. On applying 380Volts to the capacitor rating of (7.5 Kvar, 440 Volts), the capacitor has to produce the Kvar rating of 5.6Kvar by the equation: Actual Kvar = Nameplate Kvar x (Applied Voltage)2/(Rated Voltage)2.
Will the microfarad rating also reduce accordingly?
What will be the capacitance output of the capacitor bank at this condition? Will the capacitance also reduce?
