I want to know how power factor of a 132 kV Grid is related with voltage, current and frequency while a 25 MW captive power plant is in synchronised mode with the Grid?

I want to add that the factory has 4 furnaces and a Rolling Mill which sometime consumes more power than that of generated by the power plant. At that time it imports power from the grid and some times (when the furnaces are in Tapping state) it exports the power to the grid.

 

fresher,

Your question really isn't clear.

There are lots of World Wide Web articles and explanations about power factor and reactive current. Have you tried researching using your preferred Internet search engine?

A grid can be considered like one big generator supplying on big load. All of the generators are synchronized together and acting as one--no single generator can go faster or slower than any other. And frequency is directly related to speed.

The power factor is a measure of how well the total power being produced and supplied to the grid is being converted to real work (watts; kW; MW). And it's also a function of the reactive load on the grid, as well as the voltage of the grid.

What may be confusing you is that each generator can have its own share of the real- and reactive loads on the grid and that's a function of the power being produced by the prime mover and the voltage of the generator with respect to the grid.

Please be more specific with your question, perhaps after you do some more research. Control.com has a cleverly hidden 'Search' feature at the far right of the Menu bar at the top of every page. (It's recommended to use the Search 'Help' because the search format is different from most search engines, though it is very powerful and fast.) Don't give up too soon; try look at some results and using new words and terms to help you find what you're looking for--both on control.com and on the World Wide Web.

If you can help to clarify your question we can probably help to answer it.

 

Fresher,

the Power factor of your generator is based on its output parameters, that is MW, and MVAr.

If those two values are known, then,

PF = MW/SQRT(MW^2+MVAr^2)


Regards,
Phil Corso ([email protected])